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Interplanar Spatial Repositioning, 'Warping'

Discussion in 'Technology' started by L.O.R.I.E., Oct 6, 2016.

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  1. L.O.R.I.E.

    L.O.R.I.E. Lil Ole' Record & Info Editor

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    Interplanar Spatial Repositioning
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    ~1,000 - 100,000px Value (Dependant on vessel dimensions)

    Using the wormhole theory, quick interplanetary and interstellar travel has been achieved. With the invention of wormhole warp drives, commercial interstellar travel has become commonplace, though this does not mean the process is cheap or simple. Often, shuttles are used to ferry citizens from planet to planet, while individuals typically do not own a ship of their own due to their high costs.


    But what is a wormhole, you say? Imagine space is a 2D flat surface. Now, imagine that surface folding over itself, with a hole being poked straight through the two halves. That hole is a wormhole; a shortcut in space time. Travelling through a wormhole, regardless of the 'folded' distance, only takes a few short minutes.

    Natural wormholes are generally unstable and unsafe to traverse, usually causing matter to be ripped apart atom by atom. Artificial wormholes, stabilized using exotic matter (Commonly processed erchius), are free from this threat.

    Once generated, exotic matter is used to prop open & catalyze the wormhole to perfect travel stability. Upon completion, matter is sucked up like water through a straw and spat out the other end.

    This is an essential, standard functionality featured in most modern day spacefaring vessels. Commonly, it may be referred to as 'Warping'. The formal term for this function is Interplanar Spatial Repositioning, or ISR.

    A Run Through The Numbers
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    The bigger the vessel, the larger the wormhole. The larger the wormhole, the more erchius consumed. Luckily, all ISR drives are outfit with automated systems that determine the exact wormhole diameter necessary for any outfit vessel. The numbers may be complicated, but the equation is simple. Take the greater of a vessels frontal width & height, and equate a circle surface area using the largest value as the diameter.

    E.G.
    We have a small single seated vessel; 2m tall, 6m wide, and 7m long.
    It's length is irrelevant - we only care about the 6m width, which we'll use as our wormholes diameter.

    Determine an accommodating surface area using the equation πr²
    π(6 / 2)²

    This gives us 28m²

    Further divide this number by the diameter to acquire the approximate liquid volume of erchius required to catalyze the wormhole.

    28 / 6

    This gives us 4.6.

    This vessel consumes erchius at a rate of 4.6 liters/light-year.
    Given the average price of a single liter of erchius (2px), it would cost 10px for this vessel to travel 1 light-year.

     
    #1 L.O.R.I.E., Oct 6, 2016
    Last edited by a moderator: Oct 24, 2016
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